NEB Class 11 · Exam intelligence
From 3 NEB Class 11 past papers: the chapters that keep coming back and their most important questions, each with a solved model answer. No guarantees; study the whole syllabus.
From the most-tested chapters first, each with a solved model answer.
Define secondary data. Describe about its sources.
Secondary data are data that have already been collected, processed and published by someone else for some other purpose, and are used by the investigator second-hand for the present study. They are cheaper and quicker to obtain than primary data but must be used carefully after checking their reliability, suitability and adequacy.
Sources of secondary data are of two types:
(a) Published sources:
(b) Unpublished sources:
Before using secondary data, the investigator should ensure they are reliable, suitable for the purpose and adequate for the study.
Explain the need of quantitative analysis in economics.
Quantitative analysis means the use of mathematical and statistical tools (numbers, functions, equations, averages, index numbers, etc.) to study economic problems. Its need in economics: - Precise expression of relationships: economic r...
Define census and sampling. Explain the methods of primary data collection.
Census method: In the census (complete enumeration) method, data are collected from each and every unit of the population/universe under study. It gives accurate and detailed results but is costly and time-consuming, so it is used when the population is small or high accuracy is essential (for example the national population census).
Sampling method: In sampling, only a representative part (sample) of the population is studied and the results are used to draw conclusions about the whole population. It is cheaper, faster and needs less labour, though it may carry some sampling error.
Methods of primary data collection (primary data = data collected first-hand by the investigator for the specific study):
The choice of method depends on the objective, area, funds and time available for the study.
Find median from the following data.
| Wage | 5-15 | 15-25 | 25-35 | 35-45 | 45-55 | 55-65 | 65-75 |
|---|---|---|---|---|---|---|---|
| No. of labour | 4 | 5 | 7 | 10 | 4 | 3 | 4 |
Given: A continuous frequency distribution. First find cumulative frequencies (c.f.). Class $f$ c.f. --------- 5-15 4 4 15-25 5 9 25-35 7 16 35-45 10 26 45-55 4 30 55-65 3 33 65-75 4 37 $$ \begin{aligned} N &= 37 \ \qquad \frac{N}{2} &=...
Construct price index number from the following table by using Laspeyre's method.
| Commodity | 2012 Price | 2012 Quantity | 2015 Price | 2015 Quantity |
|---|---|---|---|---|
| A | 10 | 80 | 15 | 100 |
| B | 4 | 150 | 4 | 200 |
| C | 6 | 120 | 10 | 130 |
| D | 20 | 70 | 25 | 40 |
Given: Base year (2012) price $p0$, quantity $q0$; current year (2015) price $p1$. Laspeyre's price index uses base-year quantities as weights: $$P{01} = \frac{\sum p1 q0}{\sum p0 q0} \times 100$$ Computation table: Commodity $p0$ $q0$ $...
Find the value using Logarithm Table.
$$\frac{52.23 \times 15.4}{69.35 \times 2.76}$$
Given: $x = \dfrac{52.23 \times 15.4}{69.35 \times 2.76}$
Take logarithm on both sides: $$\log x = (\log 52.23 + \log 15.4) - (\log 69.35 + \log 2.76)$$
Reading values from the log table: $$ \begin{aligned} \log 52.23 &= 1.7180\ \log 15.4 &= 1.1875\ \log 69.35 &= 1.8412\ \log 2.76 &= 0.4409 \ \log x &= (1.7180 + 1.1875) - (1.8412 + 0.4409) \ \log x &= 2.9055 - 2.2821 \ &= 0.6234 \end{aligned} $$
Taking antilog: $$ \begin{aligned} x &= \text{antilog}(0.6234) \ &= 4.20 \end{aligned} $$
Answer: The value is approximately 4.20.
Find the slope and Y-intercept of the line 3x + y - 9 = 0.
Given: The line $3x + y - 9 = 0$. Reduce it to the slope-intercept form $y = mx + c$, where $m$ = slope and $c$ = y-intercept: $$ \begin{aligned} 3x + y - 9 &= 0\ y &= -3x + 9 \end{aligned} $$ Comparing with $y = mx + c$: $$ \begin{alig...
Solve the following equations using Matrix method.
$$ \begin{aligned} x + 3y &= 13 \ x + y &= 7 \end{aligned} $$
Given: In matrix form $AX = B$: $$A = \begin{bmatrix} 1 & 3 \ 1 & 1 \end{bmatrix}, \quad B = \begin{bmatrix} 13 \ 7 \end{bmatrix} $$ Determinant: $$ \begin{aligned} A &= (1)(1) - (3)(1) \ &= 1 - 3 \ &= -2 \end{aligned} $$ Since $A \n...
Calculate mean.
| Wage | 0-100 | 100-200 | 200-300 | 300-400 | 400-500 |
|---|---|---|---|---|---|
| No. of workers | 4 | 12 | 16 | 10 | 8 |
Given: A continuous frequency distribution. Take mid-value $m$ of each class. $$\bar{x} = \frac{\sum fm}{N}$$ Computation table: Class $m$ $f$ $fm$ ------------ 0-100 50 4 200 100-200 150 12 1800 200-300 250 16 4000 300-400 350 10 3500 4...
Calculate quartile deviation.
| Marks | 50 | 60 | 70 | 80 | 90 |
|---|---|---|---|---|---|
| No. of students | 2 | 4 | 8 | 4 | 1 |
Given: A discrete series. First find cumulative frequencies (c.f.). Marks $f$ c.f. --------- 50 2 2 60 4 6 70 8 14 80 4 18 90 1 19 $$N = 19$$ First quartile $Q1$: size of $$ \begin{aligned} \dfrac{N+1}{4} &= \dfrac{20}{4} \ &= 5^{th} \e...
Find the equation of a line joining the points (2, 2) and (-2, 5).
Given: Two points $(x1, y1) = (2, 2)$ and $(x2, y2) = (-2, 5)$. Slope: $$ \begin{aligned} m &= \frac{y2 - y1}{x2 - x1} \ &= \frac{5 - 2}{-2 - 2} \ &= \frac{3}{-4} \ &= -\frac{3}{4} \end{aligned} $$ Equation using point-slope form $y -...
Solve by using matrix method.
$$ \begin{aligned} 3x + 5y &= 25 \ 2x + 3y &= 16 \end{aligned} $$
Given: In matrix form $AX = B$: $$A = \begin{bmatrix} 3 & 5 \ 2 & 3 \end{bmatrix}, \quad B = \begin{bmatrix} 25 \ 16 \end{bmatrix} $$
Determinant: $$ \begin{aligned} |A| &= (3)(3) - (5)(2) \ &= 9 - 10 \ &= -1 \end{aligned} $$
Since $|A| \neq 0$, using Cramer's rule: $$ \begin{aligned} x &= \frac{1}{|A|}\begin{vmatrix} 25 & 5 \ 16 & 3 \end{vmatrix} \ &= \frac{(25)(3) - (5)(16)}{-1} \ &= \frac{75 - 80}{-1} \ &= \frac{-5}{-1} \ &= 5 \ y &= \frac{1}{|A|}\begin{vmatrix} 3 & 25 \ 2 & 16 \end{vmatrix} \ &= \frac{(3)(16) - (25)(2)}{-1} \ &= \frac{48 - 50}{-1} \ &= \frac{-2}{-1} \ &= 2 \end{aligned} $$
Answer: $x = 5, ; y = 2$. Check: $3(5) + 5(2) = 25$ and $2(5) + 3(2) = 16$. Verified.
Construct Laspeyre's price index number for the year 2005 from the following table.
| Commodity | 2004 Price | 2004 Quantity | 2005 Price | 2005 Quantity |
|---|---|---|---|---|
| A | 5 | 60 | 12 | 50 |
| B | 4 | 40 | 10 | 45 |
| C | 3 | 20 | 8 | 30 |
| D | 2 | 50 | 7 | 40 |
Given: Base year (2004) price $p0$, quantity $q0$; current year (2005) price $p1$. Laspeyre's price index uses base-year quantities as weights: $$P{01} = \frac{\sum p1 q0}{\sum p0 q0} \times 100$$ Computation table: Commodity $p0$ $q0$ $...
Find standard deviation.
| Expenditure | 10-30 | 30-50 | 50-70 | 70-90 | 90-110 |
|---|---|---|---|---|---|
| Individual | 3 | 2 | 4 | 3 | 3 |
Given: A continuous frequency distribution. Take mid-value $m$ of each class. $$ \begin{aligned} \bar{x} &= \frac{\sum fm}{N} \ \qquad \sigma &= \sqrt{\frac{\sum fm^2}{N} - \left(\frac{\sum fm}{N}\right)^2} \end{aligned} $$ Computation ...
Find the value using Logarithm Table.
$$\frac{31.3 \times \sqrt{74.3}}{\sqrt{47.3}}$$
Given: $x = \dfrac{31.3 \times \sqrt{74.3}}{\sqrt{47.3}}$
Take logarithm on both sides: $$\log x = \log 31.3 + \tfrac{1}{2}\log 74.3 - \tfrac{1}{2}\log 47.3$$
Reading values from the log table: $$ \begin{aligned} \log 31.3 &= 1.4955\ \tfrac{1}{2}\log 74.3 &= \tfrac{1}{2}(1.8710) \ &= 0.9355\ \tfrac{1}{2}\log 47.3 &= \tfrac{1}{2}(1.6749) \ &= 0.8374 \ \log x &= 1.4955 + 0.9355 - 0.8374 \ &= 1.5936 \end{aligned} $$
Taking antilog: $$ \begin{aligned} x &= \text{antilog}(1.5936) \ &= 39.23 \end{aligned} $$
Answer: The value is approximately 39.23.
Solve by using matrix method.
$$ \begin{aligned} 4x - 3y &= 5 \ 6x + 2y &= 40 \end{aligned} $$
Given: In matrix form $AX = B$: $$A = \begin{bmatrix} 4 & -3 \ 6 & 2 \end{bmatrix}, \quad X = \begin{bmatrix} x \ y \end{bmatrix}, \quad B = \begin{bmatrix} 5 \ 40 \end{bmatrix} $$
Determinant: $$ \begin{aligned} |A| &= (4)(2) - (-3)(6) \ &= 8 + 18 \ &= 26 \end{aligned} $$
Since $|A| \neq 0$, a unique solution exists. Using Cramer's rule: $$ \begin{aligned} x &= \frac{1}{|A|}\begin{vmatrix} 5 & -3 \ 40 & 2 \end{vmatrix} \ &= \frac{(5)(2) - (-3)(40)}{26} \ &= \frac{10 + 120}{26} \ &= \frac{130}{26} \ &= 5 \ y &= \frac{1}{|A|}\begin{vmatrix} 4 & 5 \ 6 & 40 \end{vmatrix} \ &= \frac{(4)(40) - (5)(6)}{26} \ &= \frac{160 - 30}{26} \ &= \frac{130}{26} \ &= 5 \end{aligned} $$
Answer: $x = 5, ; y = 5$. Check: $4(5) - 3(5) = 5$ and $6(5) + 2(5) = 40$. Verified.
Find the equation of a straight line passing through the point (7, 8) making equal intercepts on both axis.
Given: A straight line making equal intercepts on both axes, so intercept on x-axis = intercept on y-axis $= a$. The intercept form of a line is: $$\frac{x}{a} + \frac{y}{b} = 1$$ With equal intercepts $a = b$: $$ \begin{aligned} \frac{x...
What are the characteristics of underdeveloped countries?
An underdeveloped country has a low level of per capita income and living standard. Main characteristics:
Nepal shares most of these characteristics.
Describe the causes of poverty in Nepal.
Causes of poverty in Nepal:
These factors keep a large part of the Nepalese population below the poverty line.
Explain the indicators of economic development.
Economic development is a sustained rise in real per capita income with improved living standards. Its indicators: - Per capita real income (GNP/GDP per head). - Human Development Index (HDI): health, education and income. - Poverty and ...
Describe the following table.
| Areas | Population Density |
|---|---|
| Rural | 153 |
| Urban | 1380 |
| Himal | 34 |
| Hills | 186 |
| Terai | 392 |
| Nepal | 180 |
The table shows the population density (persons per sq. km.) of Nepal by area and region. - Urban areas have by far the highest density (1380), much above the national average, because of concentration of jobs, services and facilities in...
Explain the process of plan formulation.
Plan formulation is the process of preparing a periodic development plan. Main steps:
In Nepal the National Planning Commission is the apex agency for plan formulation.
Describe the importance of foreign employment in Nepalese economy.
Foreign employment (Nepalese working abroad) is very important for the economy:
Despite some social costs (loss of active manpower), foreign employment currently plays a vital role in sustaining Nepal's economy.
Discuss the measures of poverty reduction in Nepal.
Measures to reduce poverty in Nepal: - Increasing production and productivity in agriculture and industry. - Generating employment through labour-intensive industries, self-employment and skill training. - Controlling population growth. ...
Explain the importance of human resource in economic development of Nepal.
Human resource means the working population with its knowledge, skill and health. Its importance for Nepal's development: - Active factor of production: human resource uses all other resources (land, capital) to produce goods and service...
Study every chapter with notes and solved questions
Open Economics notes and questionsGiven: A continuous frequency distribution. First find cumulative frequencies (c.f.). Class c.f. --------- 5-15 4 4 15-25 5 9 25-35 7 16 35-45 10 26 45-55 4 30 55-65 3 33 65-75 4 37 $$ \begin{aligned} N &= 37 \ \qquad \frac{N}{2} &=...
Given: Base year (2012) price , quantity ; current year (2015) price . Laspeyre's price index uses base-year quantities as weights: Computation table: Commodity $...
Find the value using Logarithm Table.
Given:
Take logarithm on both sides:
Reading values from the log table:
Taking antilog:
Answer: The value is approximately 4.20.
Given: The line . Reduce it to the slope-intercept form , where = slope and = y-intercept: Comparing with : $$ \begin{alig...
Solve the following equations using Matrix method.
Given: In matrix form : Determinant: Since $A \n...
Given: A continuous frequency distribution. Take mid-value of each class. Computation table: Class ------------ 0-100 50 4 200 100-200 150 12 1800 200-300 250 16 4000 300-400 350 10 3500 4...
Given: A discrete series. First find cumulative frequencies (c.f.). Marks c.f. --------- 50 2 2 60 4 6 70 8 14 80 4 18 90 1 19 First quartile : size of $$ \begin{aligned} \dfrac{N+1}{4} &= \dfrac{20}{4} \ &= 5^{th} \e...
Given: Two points and . Slope: Equation using point-slope form $y -...
Solve by using matrix method.
Given: In matrix form :
Determinant:
Since , using Cramer's rule:
Answer: . Check: and . Verified.
Given: Base year (2004) price , quantity ; current year (2005) price . Laspeyre's price index uses base-year quantities as weights: Computation table: Commodity $...
Given: A continuous frequency distribution. Take mid-value of each class. Computation ...
Find the value using Logarithm Table.
Given:
Take logarithm on both sides:
Reading values from the log table:
Taking antilog:
Answer: The value is approximately 39.23.
Solve by using matrix method.
Given: In matrix form :
Determinant:
Since , a unique solution exists. Using Cramer's rule:
Answer: . Check: and . Verified.
Given: A straight line making equal intercepts on both axes, so intercept on x-axis = intercept on y-axis . The intercept form of a line is: With equal intercepts : $$ \begin{aligned} \frac{x...