Physics · Chapter 12
Study notes aligned to the official NEB syllabus.
Diffraction is the bending of waves around the edges of an obstacle or aperture and their spreading into the region of the geometrical shadow. It is a property of all waves (sound, water waves, light, X-rays) and is direct evidence of the wave nature of light.
Condition for appreciable diffraction: diffraction is significant only when the size of the obstacle or aperture (slit width $a$) is comparable to the wavelength $\lambda$:
This is why sound diffracts easily around doors and buildings (its wavelength is a few centimetres to metres, comparable to the openings), while light does not noticeably bend around ordinary objects (its wavelength is about $500\ \text{nm}$, far smaller than everyday obstacles).
Difference between interference and diffraction:
| Interference | Diffraction |
|---|---|
| Superposition of waves from two (or few) separate coherent sources. | Superposition of secondary wavelets from different parts of the same wavefront. |
| All bright fringes have (nearly) equal intensity. | The central maximum is far brighter and wider; side maxima fall off rapidly. |
| Fringes are equally spaced. | Fringes are unequally spaced. |
When monochromatic light of wavelength $\lambda$ passes through a single slit of width $a$ and falls on a distant screen, the pattern consists of:
Condition for minima (dark fringes). By Huygens' principle every point of the wavefront in the slit is a secondary source. Consider the slit divided into two halves. Light from the top edge and from the middle of the slit travel to a point on the screen at angle $\theta$ with a path difference of $\dfrac{a}{2}\sin\theta$. The two halves cancel in pairs (destructive interference) when this equals $\dfrac{\lambda}{2}$, i.e. when $a\sin\theta = \lambda$. Repeating the argument for the slit divided into $2n$ strips gives the general condition for the $n$th minimum:
$$\boxed{a\sin\theta_n = n\lambda}, \qquad n = \pm 1, \pm 2, \pm 3, \dots$$
Important exam point: for a single slit, $a\sin\theta = n\lambda$ gives the minima (dark fringes), whereas in the double-slit and grating cases $d\sin\theta = n\lambda$ gives the maxima. This is a common source of confusion.
Width of the central maximum. The central maximum lies between the first minima on either side ($n = \pm 1$). For small angles, $\sin\theta \approx \theta \approx \lambda/a$, so:
Effect of narrowing the slit: as $a$ decreases, $2\lambda/a$ increases, so a narrower slit gives a wider central maximum. This is counter-intuitive but correct: the smaller the aperture, the more the light spreads.
Diffraction is the bending of waves around the edges of an obstacle or aperture and their spreading into the region of the geometrical shadow. It is a property of all waves (sound, water waves, light, X-rays) and is direct evidence of the wave nature of light.
Condition for appreciable diffraction: diffraction is significant only when the size of the obstacle or aperture (slit width ) is comparable to the wavelength :
This is why sound diffracts easily around doors and buildings (its wavelength is a few centimetres to metres, comparable to the openings), while light does not noticeably bend around ordinary objects (its wavelength is about , far smaller than everyday obstacles).
Difference between interference and diffraction:
| Interference | Diffraction |
|---|---|
| Superposition of waves from two (or few) separate coherent sources. | Superposition of secondary wavelets from different parts of the same wavefront. |
| All bright fringes have (nearly) equal intensity. | The central maximum is far brighter and wider; side maxima fall off rapidly. |
| Fringes are equally spaced. | Fringes are unequally spaced. |
When monochromatic light of wavelength passes through a single slit of width and falls on a distant screen, the pattern consists of:
Condition for minima (dark fringes). By Huygens' principle every point of the wavefront in the slit is a secondary source. Consider the slit divided into two halves. Light from the top edge and from the middle of the slit travel to a point on the screen at angle with a path difference of . The two halves cancel in pairs (destructive interference) when this equals , i.e. when . Repeating the argument for the slit divided into strips gives the general condition for the th minimum:
Important exam point: for a single slit, gives the minima (dark fringes), whereas in the double-slit and grating cases gives the maxima. This is a common source of confusion.
Width of the central maximum. The central maximum lies between the first minima on either side (). For small angles, , so:
Effect of narrowing the slit: as decreases, increases, so a narrower slit gives a wider central maximum. This is counter-intuitive but correct: the smaller the aperture, the more the light spreads.