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Network and Data Communications208110 marksNumerical: Subnetting calculationSubnetting concept

Divide the network 192.168.2.0/24 into subnets having 48 hosts each.Find the subnet ID, subnet mask, broadcast address and network ranges. What are the advantages of subnetting?[7+3]

Divide the network 192.168.2.0/24 into subnets having 48 hosts each.Find the subnet ID, subnet mask, broadcast address and network ranges. What are the advantages of subnetting?[7+3]

  • Network: $192.168.2.0/24$ - Required hosts per subnet: $48$ --- Need $2^n - 2 \geq 48$: $n$ $2^n - 2$ Sufficient? ----------------------------- 5 30 No 6 62 Yes ✓ So host bits = 6. --- - Total bits = 32, original network bits = 24 - Borrowed subnet bits = $32 - 24 - 6 = 2$ - New prefix =
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