Find the limit of limhtoinfty fracsqrt6h+25-5h2. | Basic Mathematics 2080

Basic Mathematics20805 marksNumerical: limit evaluationLimits at infinity

Find the limit of $\lim_{h\to\infty} \frac{\sqrt{6h+25-5}}{h^2}$ . [5]

Find the limit of $\lim_{h\to\infty} \frac{\sqrt{6h+25-5}}{h^2}$. [5]

The expression as literally rendered is garbled, but the most sensible interpretation is: $\lim{h \to \infty} \frac{\sqrt{6h + 25 - 5}}{h^2}$ - Numerator: $\sqrt{6h + 25 - 5} = \sqrt{6h + 20}$ - Denominator: $h^2$ - Limit variable: $h \to \infty$ Note: The original text is corrupted (e.g., "hto...

The expression as literally rendered is garbled, but the most sensible interpretation is: $$\lim{h \to \infty} \frac{\sqrt{6h + 25 - 5}}{h^2}$$ - Numerator: $\sqrt{6h + 25 - 5} = \sqrt{6h + 20}$ - Denominator: $h^2$ - Limit variable: $h \to \infty$ Note: The original text is corrupted (e.g., "hto...

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