Using pumping lemma, prove that the language is not regular. L = ai bj | Theory of Computation 2080

Theory of Computation20805 marksNumerical: Pumping lemma non-regular proofPumping Lemma

Using pumping lemma, prove that the language is not regular. $L = \{a^i b^j c^k \mid j=i+k\}$ [5]

Using pumping lemma, prove that the language is not regular. $L = {a^i b^j c^k \mid j=i+k}$ [5]

Language: $L = \{a^i b^j c^k \mid j = i + k,\ i,k \ge 0\}$ - Alphabet: $\{a, b, c\}$ - Method required: Pumping Lemma for regular languages. --- Suppose $L$ is regular. Then by the Pumping Lemma, there exists a pumping length $p \ge 1$ such that any string $s \in L$ with $s \ge p$ can be writte...

Language: $L = {a^i b^j c^k \mid j = i + k,\ i,k \ge 0}$ - Alphabet: ${a, b, c}$ - Method required: Pumping Lemma for regular languages. --- Suppose $L$ is regular. Then by the Pumping Lemma, there exists a pumping length $p \ge 1$ such that any string $s \in L$ with $s \ge p$ can be writte...

Using pumping lemma, prove that the language is not regular. L = ai bj ck mid j=i+k