Simplify the Boolean Function F in sum of products using the don't-car | Digital Logic 2081.2

Digital Logic2081.25 marksNumerical: Boolean function simplification with don't-caresDon't care conditions in K-maps

Simplify the Boolean Function $F$ in sum of products using the don't-care conditions $d$ . $F = B'C'D' + BCD' + ABCD'$ , $d = B'CD' + A'BC'D$ . [5]

Simplify the Boolean Function $F$ in sum of products using the don't-care conditions $d$. $F = B'C'D' + BCD' + ABCD'$, $d = B'CD' + A'BC'D$. [5]

Function (SOP): $F = B'C'D' + BCD' + ABCD'$ Don't-care conditions: $d = B'CD' + A'BC'D$ Variables: A, B, C, D (4 variables → minterms 0 to 15) --- Order of bits: A B C D. - $B'C'D'$ → B=0, C=0, D=0, A free → A=0: 0000 = m₀, A=1: 1000 = m₈ - $BCD'$ → B=1, C=1, D=0, A free → A=0: 0110 = m₆, A=1...

Function (SOP): $$F = B'C'D' + BCD' + ABCD'$$ Don't-care conditions: $$d = B'CD' + A'BC'D$$ Variables: A, B, C, D (4 variables → minterms 0 to 15) --- Order of bits: A B C D. - $B'C'D'$ → B=0, C=0, D=0, A free → A=0: 0000 = m₀, A=1: 1000 = m₈ - $BCD'$ → B=1, C=1, D=0, A free → A=0: 0110 = m₆, A=1...

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Simplify the Boolean Function F in sum of products using the don't-care conditions d. F = B'C'D' + BCD' + ABCD', d = B'CD' + A'BC'D.