Calculate a real negative root of following equation using Newton’s me | Numerical Method 2075

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Calculate a real negative root of following equation using Newton’s method for polynomial. $x^4 + 2x^3 + 3x^2 + 4x = 5$ . [5]

Calculate a real negative root of following equation using Newton’s method for polynomial. $x^4 + 2x^3 + 3x^2 + 4x = 5$. [5]

Equation: $x^4 + 2x^3 + 3x^2 + 4x = 5$ Rearranged: $f(x) = x^4 + 2x^3 + 3x^2 + 4x - 5 = 0$ $x{n+1} = xn - \frac{f(xn)}{f'(xn)}, \qquad f'(x) = 4x^3 + 6x^2 + 6x + 4$ $f(-1) = 1 - 2 + 3 - 4 - 5 = -7 \;(<0)$ $f(-2) = 16 - 16 + 12 - 8 - 5 = -1 \;(<0)$ $$f(-3) = 81 - 54 + 27 - 12 - 5 = 37 ;...

Equation: $$x^4 + 2x^3 + 3x^2 + 4x = 5$$ Rearranged: $$f(x) = x^4 + 2x^3 + 3x^2 + 4x - 5 = 0$$ $$x{n+1} = xn - \frac{f(xn)}{f'(xn)}, \qquad f'(x) = 4x^3 + 6x^2 + 6x + 4$$ $$f(-1) = 1 - 2 + 3 - 4 - 5 = -7 ;(<0)$$ $$f(-2) = 16 - 16 + 12 - 8 - 5 = -1 ;(<0)$$ $$f(-3) = 81 - 54 + 27 - 12 - 5 = 37 ;...

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Calculate a real negative root of following equation using Newton’s method for polynomial. x4 + 2x3 + 3x2 + 4x = 5.