Numerical Method207910 marksNumerical: secant method root findingSecant method and Convergence
How secant method can approximate the root of a non-linear equation? Explain with necessary derivation. Estimate a real root of following equation using secant method. Assume error precision of 0.01. x3 + 2x - cos(x) = 4
How secant method can approximate the root of a non-linear equation? Explain with necessary derivation. Estimate a real root of following equation using secant method. Assume error precision of 0.01. $x^3 + 2x - \cos(x) = 4$ [10]
- Equation: $x^3 + 2x - \cos(x) = 4$, i.e. $f(x) = x^3 + 2x - \cos(x) - 4 = 0$ - Error precision: $E = 0.01$ - Method: Secant method - Initial guesses: not specified (to be chosen from sign change). All angles in radians. Newton-Raphson formula: $$x{n+1} = xn - \frac{f(xn)}{f'(xn)}$$ The secant m...