Statistics I20785 marksNumerical: normal distribution probabilityContinuous distribution
The lifetime of a certain electronic component is a normal random variate with the expectation of 5000 hours and a standard deviation of 100 hours. Compute the probabilities under the following conditions:a. Lifetime of components between 3000 to 6500 hours b. Lifetime of components between 3000 to
The lifetime of a certain electronic component is a normal random variate with the expectation of 5000 hours and a standard deviation of 100 hours. Compute the probabilities under the following conditions:a. Lifetime of components between 3000 to 6500 hours b. Lifetime of components between 3000 to 6500 hours c. Lifetime of components more than 6000 hours [5]
- Mean $\mu = 5000$ hours - Standard deviation $\sigma = 100$ hours - $X \sim N(5000, 100^2)$ Standardization: $$Z = \frac{X - \mu}{\sigma} = \frac{X - 5000}{100}$$ Note on the question: Parts (a) and (b) are stated identically ("between 3000 to 6500 hours"). This is clearly a typographical dupli...