BSc CSIT Entrance Exam 2076 Questions with Answers

1. a$-3$
2. b$0$
3. c$1$
4. d$2$

Answer (d): The values fit $f(x)=x^2+1$, so $f(-1)=1+1=2$.

Revise: Algebra (Class 11 notes)

1. a$A^c\subseteq B^c$
2. b$A^c=B^c$
3. c$B^c\subseteq A^c$
4. d$B^c\not\subset A^c$

Answer (c): Taking complements reverses inclusion, so $A\subseteq B$ gives $B^c\subseteq A^c$.

Revise: Algebra (Class 11 notes)

1. a$\frac{x}{1-x}$
2. b$\frac{1}{x}$
3. c$\frac{x}{x-1}$
4. d$\frac{x}{1+x}$

Answer (c): $\log_a(ab)=1+\log_a b=x$, so $\log_a b=x-1$ and $\log_b a=\frac{1}{x-1}$. Then $\log_b(ab)=1+\frac{1}{x-1}=\frac{x}{x-1}$.

Revise: Algebra (Class 11 notes)

1. a$-1$
2. b$1$
3. c$0$
4. d$2$

Answer (b): $AB=\begin{pmatrix}1&0\0&-(2x-3)\end{pmatrix}$. For this to be $I$, $-(2x-3)=1$, so $x=1$.

Revise: Algebra (Class 11 notes)

1. a$A-I$
2. b$A$
3. c$I+A$
4. d$I-A$

Answer (d): Multiply by $A^{-1}$: $A-I+A^{-1}=0$, so $A^{-1}=I-A$.

Revise: Algebra (Class 11 notes)

1. a12
2. b8
3. c18
4. d6

Answer (a): For $a/r, a, ar$ the product is $a^3=1728$, so $a=12$.

Revise: Algebra (Class 11 notes)

1. a$1,\omega,\omega^2,\omega^3$
2. b$1,\omega,\omega^2,\omega^4$
3. c$\pm1,\pm i$
4. dcannot be determined

Answer (c): $x^4=1$ gives $(x^2-1)(x^2+1)=0$, so $x=\pm1,\pm i$.

Revise: Algebra (Class 11 notes)

1. a$\frac{1}{13}+\frac{2i}{13}$
2. b$\frac{3}{13}+\frac{11i}{13}$
3. c$\frac{3}{13}+\frac{2i}{13}$
4. d$\frac{3}{13}-\frac{11i}{13}$

Answer (d): The inverse is $\frac{3-i}{2+3i}=\frac{(3-i)(2-3i)}{13}=\frac{3-11i}{13}$.

Revise: Algebra (Class 11 notes)

1. a$a-b=0$
2. b$a+b=1$
3. c$a-b=1$
4. d$a+b=0$

Answer (d): Clearing fractions gives $x^2-2(a+b)x+3ab=0$. Roots equal and opposite means the sum is zero, so $a+b=0$.

Revise: Algebra (Class 11 notes)

1. a$(-2k+1)$
2. b$(k+1)$
3. c$(4k^3-2k)$
4. d$(4k^3-2k-1)$

Answer (d): By the remainder theorem put $x=-2k$: $k(4k^2)-2k-1=4k^3-2k-1$.

Revise: Algebra (Class 11 notes)

1. a$0$
2. b$\frac{1}{2}$
3. c$\frac{\sqrt3}{2}$
4. d$1$

Answer (d): $\sin^{-1}(4/5)=\cos^{-1}(3/5)$, so the right side is $0$ and $x=\cos 0=1$.

Revise: Trigonometry (Class 11 notes)

1. a$\frac{\pi}{3},\frac{2\pi}{3}$
2. b$\frac{\pi}{4},\frac{3\pi}{4}$
3. c$\frac{\pi}{3},\frac{5\pi}{3}$
4. d$\frac{\pi}{6},\frac{2\pi}{6}$

Answer (c): $2-2\cos^2\theta=3\cos\theta$ gives $(2\cos\theta-1)(\cos\theta+2)=0$, so $\cos\theta=\frac12$ and $\theta=\frac{\pi}{3},\frac{5\pi}{3}$.

Revise: Trigonometry (Class 11 notes)

1. a$3$
2. b$-4$
3. c$6$
4. d$\frac{7}{2}$

Answer (a): The pair condition $abc+2fgh-af^2-bg^2-ch^2=0$ with $a=1,b=2,c=2,f=\frac52,g=\frac32,h=\frac k2$ gives $2k^2-15k+27=0$, so $k=3$ or $\frac92$. Only $3$ is listed.

Revise: Analytic geometry (Class 11 notes)

1. aOne
2. btwo
3. cthree
4. dfour

Answer (c): Externally touching circles have two direct tangents and one common tangent at the point of contact, so three.

Revise: Analytic geometry (Class 11 notes)

1. a(2, 4), (0, 0)
2. b(0, 0), (1, 2)
3. c(3, 2), (-1, 4)
4. d(1, 3), (-2, 0)

Answer (a): Put $y=2x$: $5x^2-10x=0$, so $x=0$ or $x=2$, giving $(0,0)$ and $(2,4)$.

Revise: Analytic geometry (Class 11 notes)

1. a$\frac{\pi}{4}$
2. b$\frac{\pi}{6}$
3. c$\frac{\pi}{2}$
4. d$\frac{\pi}{3}$

Answer (a): $\tan\theta=\frac{2\sqrt{h^2-ab}}{a+b}=\frac{2\sqrt{49/4-6}}{5}=1$, so $\theta=\frac{\pi}{4}$.

Revise: Analytic geometry (Class 11 notes)

1. a$\frac{b}{e}$
2. b$\frac{a}{d}$
3. c$\frac{abc}{def}$
4. d$\frac{ae}{bd}$

Answer (b): Divide by $x^2$: the lower powers vanish and the ratio of leading coefficients $\frac{a}{d}$ remains.

Revise: Calculus (Class 12 notes)

1. a6
2. b2
3. c3
4. d4

Answer (c): The limit equals $n\cdot3^{n-1}$. For $n=3$ it is $3\cdot9=27$.

Revise: Calculus (Class 12 notes)

1. a$\frac{-1}{x\sqrt{x^2+1}}$
2. b$\frac{-1}{x^2-1}$
3. c$\frac{-1}{x\sqrt{1-x^2}}$
4. d$\frac{1}{\sqrt{1-x^2}}$

Answer (a): The standard result is $\frac{d}{dx}\operatorname{cosech}^{-1}x=\frac{-1}{|x|\sqrt{1+x^2}}$.

Revise: Calculus (Class 12 notes)

1. a$\frac{1}{x}$
2. b$1$
3. c$\frac{1}{x\log\sqrt x}$
4. d$0$

Answer (d): $y=\frac{\ln x}{\frac12\ln x}=2$, a constant, so $\frac{dy}{dx}=0$.

Revise: Calculus (Class 12 notes)

1. a$\cos^{-1}x+c$
2. b$\sin^{-1}x+c$
3. c$\tan^{-1}x+c$
4. dnone

Answer (b): This is the standard integral giving $\sin^{-1}x+c$.

Revise: Calculus (Class 12 notes)

1. a$2\sin x+\log(\sec x+\tan x)$
2. b$2\sin x-\log(\sec x+\tan x)$
3. c$2\cos x-\log(\tan x)$
4. d$2\cos x+\log(\sec x+\tan x)$

Answer (b): $\cos2x=2\cos^2x-1$, so the integrand is $2\cos x-\sec x$, giving $2\sin x-\log(\sec x+\tan x)$.

Revise: Calculus (Class 12 notes)

1. a$a^{\sin x}+c$
2. b$\frac{a^{\sin x}}{\log a}+c$
3. c$a^{\sin x}-\log a+c$
4. dnone

Answer (b): Put $u=\sin x$: $\int a^u du=\frac{a^u}{\log a}+c$.

Revise: Calculus (Class 12 notes)

1. a12
2. b-12
3. c0
4. d4

Answer (d): $y''=6x-24=0$ gives $x=4$, and $y''$ changes sign there.

Revise: Calculus (Class 12 notes)

1. a0
2. b2
3. c$\pi$
4. d4

Answer (d): Area $=2\int_0^{\pi}\sin x,dx=2\cdot2=4$ (the negative half is taken as positive).

Revise: Calculus (Class 12 notes)

1. ab
2. bc
3. cb+d
4. d2c

Answer (d): $v=\frac{dx}{dt}=b+2ct$, and $a=\frac{dv}{dt}=2c$.

Revise: Kinematics (Class 11 notes)

1. a1:6
2. b1:2
3. c1:4
4. d$1:\sqrt2$

Answer (b): $p=\sqrt{2mK}\propto\sqrt m$, so $p_1:p_2=\sqrt1:\sqrt4=1:2$.

Revise: Work, Energy and Power (Class 11 notes)

1. aMinimum at the equator
2. bMinimum at the poles
3. cMinimum midway between poles an equator
4. dSame at all points on the earth's surface

Answer (a): Earth bulges at the equator and its rotation reduces effective gravity there, so $g$ is least at the equator.

Revise: Gravitation (Class 11 notes)

1. a$r^3$
2. b$r^2$
3. cr
4. d$1/r$

Answer (b): Surface energy $=T\times4\pi r^2\propto r^2$.

Revise: Fluid Statics (Class 12 notes)

1. a0.25 g/cc
2. b0.75 g/cc
3. c0.9 g/cc
4. d0.1 g/cc

Answer (b): For floating, $\rho_{body}V=\rho_{water}\cdot\frac34V$, so $\rho_{body}=0.75$ g/cc.

Revise: Fluid Statics (Class 12 notes)

1. a2 atm
2. b4 atm
3. c8 atm
4. d16 atm

Answer (c): $P_2=P_1(V_1/V_2)^\gamma=4^{1.5}=8$ atm.

Revise: First Law of Thermodynamics (Class 12 notes)

1. a727
2. b$(727)^4$
3. c1000
4. d$(1000)^4$

Answer (d): $727^\circ\text{C}=1000$ K and the Stefan law gives rate $\propto T^4=(1000)^4$.

Revise: Rate of Heat Flow (Class 11 notes)

1. aEqual to total pressure on surface
2. bGreater than total pressure on surface
3. cLess than total pressure on surface
4. dEqual to atmospheric pressure

Answer (a): Boiling starts when saturated vapour pressure equals the external pressure on the liquid surface, usually atmospheric.

Revise: Heat and Temperature (Class 11 notes)

1. aMaximum for red color
2. bMaximum for violet color
3. cMaximum for yellow color
4. dSame for all colors

Answer (a): Red has the smallest refractive index, so by $\frac1f\propto(\mu-1)$ its focal length is largest.

Revise: Lenses (Class 11 notes)

1. a$30^\circ$
2. b$45^\circ$
3. c$60^\circ$
4. d$90^\circ$

Answer (a): $\sqrt2=\frac{\sin\frac{60+\delta}{2}}{\sin30^\circ}$ gives $\sin\frac{60+\delta}{2}=\frac{1}{\sqrt2}$, so $\frac{60+\delta}{2}=45^\circ$ and $\delta=30^\circ$.

Revise: Refraction Through Prisms (Class 11 notes)

1. aincreases
2. bdecreases
3. cremain same
4. dfirst increases and then decreases

Answer (b): Fringe width $\beta=\frac{\lambda D}{d}$, so it decreases as $d$ increases.

Revise: Interference (Class 12 notes)

1. a1000 lun
2. b2000 lun
3. c3000 lun
4. d4000 lun

Answer (d): Total flux is $4\pi I=2000\pi$ lm, 2% of it is $40\pi$ lm, and the disc area is $\pi(0.1)^2=0.01\pi$ m$^2$, so $E=40\pi/0.01\pi=4000$ lux.

Revise: Nature and Propagation of Light (Class 12 notes)

1. a8V
2. b80V
3. c800V
4. dzero

Answer (b): Inside a conducting sphere the field is zero, so the potential is constant and equals the surface value, 80 V.

Revise: Potential Difference and Potential Energy (Class 11 notes)

1. a1:1
2. b2:3
3. c3:2
4. d4:9

Answer (b): In parallel the voltage is the same, so $Q=CV$ gives $Q_1:Q_2=2:3$.

Revise: Capacitor (Class 11 notes)

1. aangle of dip
2. bangle of declination
3. ccritical angle
4. dcurie angle

Answer (b): By definition this angle is the magnetic declination.

Revise: Magnetic Field (Class 12 notes)

1. aan accelerating force
2. ba refracting force
3. ca radial force
4. dno force

Answer (d): The field inside is along the axis, parallel to the velocity, so $F=qvB\sin0=0$.

Revise: Magnetic Field (Class 12 notes)

1. a$\sqrt{\frac{E}{Rt}}$
2. b$\left(\frac{E}{Rt}\right)^2$
3. c$ERt$
4. d$(ERt)^{1/2}$

Answer (a): $E=I^2Rt$ so $I=\sqrt{\frac{E}{Rt}}$.

Revise: DC Circuit (Class 11 notes)

1. a3 cm
2. b100 cm
3. c2 cm
4. d5 cm

Answer (c): The wave number is $k=\pi$, so $\lambda=\frac{2\pi}{k}=2$ cm.

Revise: Wave Motion (Class 12 notes)

1. a225 Hz
2. b200 Hz
3. c150 Hz
4. d100 Hz

Answer (a): $f'=f\frac{v}{v-v_s}=150\times\frac{330}{220}=225$ Hz.

Revise: Acoustic Phenomena (Class 12 notes)

1. astrain is max. at nodes
2. bstrain is max. at antinodes
3. cstrain is min. at nodes
4. dstrain is min. at all points

Answer (a): At nodes the medium is displaced least but the neighbouring particles squeeze or stretch it most, so strain (pressure variation) is maximum at nodes.

Revise: Wave in Pipes and Strings (Class 12 notes)

1. a$n\lambda=\pi R$
2. b$n\lambda=\frac32\pi R$
3. c$n\lambda=2\pi R$
4. d$n\lambda=4\pi R$

Answer (c): The orbit holds a whole number of wavelengths: $2\pi R=n\lambda$.

Revise: Quantization of Energy (Class 12 notes)

1. a$n=1$ to $n=2$
2. b$n=3$ to $n=8$
3. c$n=2$ to $n=1$
4. d$n=8$ to $n=3$

Answer (a): Absorption means going up in n. The 1 to 2 jump has the largest energy gap (10.2 eV), hence highest frequency.

Revise: Quantization of Energy (Class 12 notes)

1. a1
2. b$\frac34$
3. c$\frac18$
4. d$\frac78$

Answer (d): 15 years is 3 half-lives, so $\frac18$ remains and $1-\frac18=\frac78$ has decayed.

Revise: Radioactivity and Nuclear Reaction (Class 12 notes)

1. aE.M waves
2. bElectron orbiting round the nucleus
3. cCharge particle emitted by nucleus
4. dNeutral particle

Answer (c): Beta rays are fast electrons (or positrons) ejected from the nucleus, so they are charged particles emitted by the nucleus.

Revise: Radioactivity and Nuclear Reaction (Class 12 notes)

1. athem
2. bhim
3. chimself
4. dthemselves

Answer (a): The soldiers are the object of 'helped' and are not the subject, so the plain pronoun 'them' is used.

Revise: Grammar and Usage (Class 11 notes)

1. aItself
2. bherself
3. chimself
4. dthemselves

Answer (c): The subject is 'He', so the reflexive pronoun is 'himself'.

Revise: Grammar and Usage (Class 11 notes)

1. aHave
2. bhas
3. chaving
4. dwere

Answer (b): The verb agrees with 'The leader', not with the phrase 'with his helpers', so 'has'.

Revise: Grammar and Usage (Class 11 notes)

1. aHas
2. bhave
3. chaving
4. dis

Answer (b): Two subjects joined by 'and' are plural, so 'have'.

Revise: Grammar and Usage (Class 11 notes)

1. aShouldn't one
2. bshould one
3. cshould he
4. dshouldn't he

Answer (b): The main clause is negative, so the tag is positive, and 'one' is repeated as 'should one?'.

Revise: Grammar and Usage (Class 11 notes)

1. aare they
2. baren't they
3. care those
4. daren't yours

Answer (a): A negative statement takes a positive tag, and 'Those books' becomes 'they': 'are they?'.

Revise: Grammar and Usage (Class 11 notes)

1. aFor
2. btill
3. cto
4. dduring

Answer (a): 'For' is used with a period of time such as ten years.

Revise: Grammar and Usage (Class 11 notes)

1. aBesides
2. bbeside
3. cto
4. dbetween

Answer (b): 'Beside' means next to; 'besides' means in addition to.

Revise: Grammar and Usage (Class 11 notes)

1. aIt will not improve
2. bIt will improve
3. cIt would improve
4. dIt would not improve

Answer (a): 'Unless' already carries the negative sense, and a present condition takes 'will' in the main clause: 'It will not improve'.

Revise: Grammar and Usage (Class 11 notes)

1. aHe will win the prize.
2. bHe would have won the prize.
3. cHe would win the prize.
4. dHe wouldn't have won the prize.

Answer (b): Third conditional: 'If + past perfect' goes with 'would have + past participle'.

Revise: Grammar and Usage (Class 11 notes)

1. aa
2. ban
3. cthe
4. dno article

Answer (d): No article is used before the name of a game.

Revise: Grammar and Usage (Class 11 notes)

1. aa
2. ban
3. cthe
4. dno article

Answer (c): 'The' is used for a specific known place such as the theatre he went to.

Revise: Grammar and Usage (Class 11 notes)

1. aSpread
2. breap
3. cgrow
4. dtake

Answer (b): To sow is to plant seeds; the opposite action is to reap (harvest).

Revise: Vocabulary and Word Formation (Class 11 notes)

1. aFlawless
2. bwrong
3. cfaculty
4. dstrong

Answer (a): 'Faulty' means having defects; 'flawless' means without defects.

Revise: Vocabulary and Word Formation (Class 11 notes)

1. aTest
2. bcheap
3. cattentive
4. dwin

Answer (a): 'Check' (to examine) means the same as 'test'.

Revise: Vocabulary and Word Formation (Class 11 notes)

1. aFree
2. bgift
3. csuggest
4. dgreet

Answer (b): As a noun, 'present' means 'gift'.

Revise: Vocabulary and Word Formation (Class 11 notes)

1. aIs sand eaten?
2. bWas sand eaten?
3. cDid we eat sand?
4. dSand is eaten.

Answer (a): Present simple question passive: 'Is + object + past participle'.

Revise: Grammar and Usage (Class 11 notes)

1. aFish was sold here.
2. bFish is sold here.
3. cFish is being sold here
4. dFish sold here.

Answer (b): Present simple passive: 'is/are + past participle', so 'Fish is sold here.'

Revise: Grammar and Usage (Class 11 notes)

1. aShe tells me that she will do it herself.
2. bShe told to do it herself.
3. cShe told me that she would do it herself.
4. dshe did it herself.

Answer (c): In indirect speech 'said to' becomes 'told', 'I' becomes 'she', 'will' becomes 'would' and 'myself' becomes 'herself'.

Revise: Grammar and Usage (Class 11 notes)

1. aRekha told me to open my mouth.
2. bRekha opened her mouth.
3. cRekha said to open her mouth.
4. dRekha told me to open her mouth.

Answer (a): An imperative becomes 'told + object + to-infinitive', and 'your' changes to 'my' for the listener.

Revise: Grammar and Usage (Class 11 notes)

1. aGoes
2. bis going
3. chas gone
4. dis

Answer (a): 'Every year' signals a habit, so the present simple 'goes'.

Revise: Grammar and Usage (Class 11 notes)

1. aAcrophobia
2. bbathophobio
3. cheightphobia
4. dnone

Answer (a): Acrophobia is the fear of heights.

Revise: Vocabulary and Word Formation (Class 11 notes)

1. aHas died
2. bhad died
3. cdie
4. dhas die

Answer (b): Of two past actions, the earlier one takes the past perfect: 'had died'.

Revise: Grammar and Usage (Class 11 notes)

1. aMis
2. bmono
3. cmicro
4. dmid

Answer (a): Mis- gives 'misfire' (to fail to fire properly).

Revise: Vocabulary and Word Formation (Class 11 notes)

1. aDieing
2. bdied
3. cdies
4. ddying

Answer (d): For verbs ending in -ie, change ie to y before -ing: die gives dying.

Revise: Vocabulary and Word Formation (Class 11 notes)

1. aol
2. bal
3. coic acid
4. doal

Answer (c): COOH is the principal functional group, so the secondary suffix is 'oic acid' (2-hydroxy-4-oxobutanoic acid).

Revise: Fundamental Principles (Class 11 notes)

1. aCarbocation
2. bfree radical
3. cCarbanion
4. dAll of above

Answer (a): Electrophilic addition to an alkene goes through a carbocation; Markovnikov's rule follows the more stable one.

Revise: Hydrocarbons (Class 11 notes)

1. a$2\pi$ and $3\sigma$ bond
2. b$3\pi$ and $2\sigma$ bond
3. c$4\sigma$ and $2\pi$ bond
4. dnone

Answer (a): HC$\equiv$CH has two C-H $\sigma$ bonds and one C-C $\sigma$ bond, plus two $\pi$ bonds in the triple bond.

Revise: Hydrocarbons (Class 11 notes)

1. aElectrophiles
2. bNucleophiles
3. cBoth a and b
4. dNone

Answer (a): Lewis acids accept an electron pair and oxidising agents accept electrons, so both are electron-seeking electrophiles.

Revise: Fundamental Principles (Class 11 notes)

1. aMethane
2. bEthane
3. cButane
4. dHexane

Answer (a): Wurtz coupling joins two alkyl halides ($2R\text{-}X\to R\text{-}R$), so it cannot give methane (one carbon).

Revise: Hydrocarbons (Class 11 notes)

1. a$\ce{HCl}+\ce{HNO3}$
2. b$\ce{HCl}+\ce{NaCl}$
3. c$\ce{HCl}+\ce{H2S}$
4. dAll of above

Answer (c): The $\ce{H+}$ from strong HCl suppresses ionisation of the weak acid $\ce{H2S}$. The other pairs are both strong electrolytes.

Revise: Ionic Equilibrium (Class 12 notes)

1. a$\ce{C_nH_{2n+2}}$
2. b$\ce{C_nH_{2n}O}$
3. c$\ce{C_nH_{2n}O2}$
4. d$\ce{C_nH_{2n+2}O}$

Answer (c): Saturated monocarboxylic acids (e.g. $\ce{CH3COOH}$, $\ce{C2H4O2}$) follow $\ce{C_nH_{2n}O2}$.

Revise: Carboxylic Acids (Class 12 notes)

1. aGlucose
2. bfructose
3. cGalactose
4. dall of above

Answer (d): Glucose, fructose and galactose are all isomers with the formula $\ce{C6H12O6}$.

1. aLaw of multiple proportion
2. bLaw of definite proportion
3. cLaw of conservation of mass
4. dLaw of combining volume

Answer (c): This is the statement of the law of conservation of mass.

Revise: Stoichiometry (Class 11 notes)

1. a4d
2. b3d
3. c5s
4. d4p

Answer (a): By the $(n+l)$ rule: 4d is 6, 3d is 5, 5s is 5, 4p is 5. So 4d is highest.

Revise: Atomic Structure (Class 11 notes)

1. a1
2. b-1
3. c-2
4. d2

Answer (b): In peroxides ($\ce{O2^{2-}}$) each oxygen has oxidation state $-1$.

Revise: Oxidation and Reduction (Class 11 notes)

1. aZero
2. bpositive
3. cnegative
4. dall

Answer (a): The standard hydrogen electrode is the reference and is assigned exactly zero potential.

Revise: Electrochemistry (Class 12 notes)

1. aNa
2. b$\ce{Mg+}$
3. c$\ce{Al^{++}}$
4. dAll have equal size

Answer (a): Na has 11 protons and 11 electrons; $\ce{Mg+}$ has 12 protons for 11 electrons and $\ce{Al^{2+}}$ is smaller still, so Na is largest.

Revise: Classification of Elements (Class 11 notes)

1. a0.018M
2. b18M
3. c50M
4. d55.55M

Answer (d): 1000 g of water is $\frac{1000}{18}=55.55$ mol in 1 L, so molarity is 55.55 M.

Revise: Stoichiometry (Class 11 notes)

1. aProtium
2. bdeuterium
3. cTritium
4. dall of above

Answer (c): Only tritium ($^3$H) is radioactive; protium and deuterium are stable.

Revise: Nuclear Chemistry (Class 12 notes)

1. a$\ce{V2O5}$
2. b$\ce{Fe(OH)3}$
3. c$\ce{CaO}$
4. dFe

Answer (a): The contact process oxidises $\ce{SO2}$ to $\ce{SO3}$ using vanadium pentoxide.

Revise: Modern Chemical Manufactures (Class 11 notes)

1. aZnS
2. b$\ce{ZnSO4.7H2O}$
3. cFeS
4. d$\ce{FeSO4.7H2O}$

Answer (b): White vitriol is hydrated zinc sulphate, $\ce{ZnSO4.7H2O}$ (green vitriol is the iron salt).

Revise: Chemistry of Metals (Class 11 notes)

1. aHydrogen bond
2. bcovalent bond
3. cpeptide bond
4. dall of above

Answer (d): Proteins are held by peptide bonds (a covalent bond) in the chain and by hydrogen bonds in the folded structure, so all of the above apply.

Revise: Biomolecules (Class 11 notes)

1. aChromophore
2. bauxochrome
3. cboth
4. dnone

Answer (a): A chromophore is the group with multiple bonds that gives colour; an auxochrome only deepens it.

Revise: Chemistry in the Service to Mankind (Class 12 notes)

1. a$\ce{HgCl2}$
2. b$\ce{Hg2Cl2}$
3. c$\ce{Hg}+\ce{HgCl2}$
4. d$\ce{Hg2Cl2}+\ce{Hg}$

Answer (b): Calomel is mercurous chloride, $\ce{Hg2Cl2}$.

Revise: Chemistry of Metals (Class 11 notes)

1. a$\ce{NO3}$
2. b$\ce{NO2}$
3. cNO
4. d$\ce{N2O}$

Answer (c): In the brown ring test $\ce{FeSO4}$ combines with NO to give $[\ce{Fe(H2O)5NO}]^{2+}$.

Revise: Chemistry of Non-Metals (Class 11 notes)

1. aMatte
2. blunar caustic
3. cfool's gold
4. dnone

Answer (c): Chalcopyrite ($\ce{CuFeS2}$) is a brassy yellow ore often mistaken for gold, hence 'fool's gold'.

Revise: Copper (Class 12 notes)

1. a3
2. b4
3. c5
4. d7

Answer (c): Hexane has 5 isomers: hexane, 2-methylpentane, 3-methylpentane, 2,2-dimethylbutane and 2,3-dimethylbutane.

Revise: Fundamental Principles (Class 11 notes)

1. aTime
2. btemperature
3. cconc. of reactant
4. dall of above

Answer (c): For a first order reaction the rate is $k[A]$, so it depends on the concentration of the reactant; time is not a direct factor, so 'all of above' is wrong.

Revise: Chemical Kinetics (Class 12 notes)

1. a$\ce{CO2}$
2. b$\ce{H2O}$
3. c$\ce{N2O3}$
4. dZnO

Answer (b): Water is neutral (pH 7). $\ce{CO2}$ and $\ce{N2O3}$ are acidic and ZnO is amphoteric.

Revise: Chemistry of Non-Metals (Class 11 notes)