- a${12,-2}$
- b$[-2,12]$
- c$(-2,12)$
- dnone
Answer (a): $|x-5|=7$ gives $x-5=7$ or $x-5=-7$, so $x=12$ or $x=-2$.
Revise: Algebra (Class 11 notes)
TU IOST | Entrance paper
Answer (a): $|x-5|=7$ gives $x-5=7$ or $x-5=-7$, so $x=12$ or $x=-2$.
Revise: Algebra (Class 11 notes)
Answer (c): $f^{-1}(7)=a$ means $f(a)=7$, so $3a-2=7$ and $a=3$.
Revise: Algebra (Class 11 notes)
Answer (b): A square root is never negative and takes every value from $0$ upward as $x\ge 3$ increases, so the range is $[0,\infty)$.
Revise: Algebra (Class 11 notes)
Answer (d): $f(-x)=(-x)^4+5=f(x)$, so the function is even and its graph is symmetric about the y-axis.
Revise: Algebra (Class 11 notes)
Answer (a): If the common ratio of a, b, c is $r$, the reciprocals have common ratio $1/r$, so they are again in geometric series.
Revise: Algebra (Class 11 notes)
Answer (c): $|A|=14-15=-1$, and $A^{-1}=\frac{1}{-1}\begin{pmatrix}7&-5\-3&2\end{pmatrix}=\begin{pmatrix}-7&5\3&-2\end{pmatrix}$.
Revise: Algebra (Class 11 notes)
Answer (b): $(A+A^T)^T=A^T+A=A+A^T$, so it is symmetric (it is also square, but symmetric is the specific property).
Revise: Algebra (Class 11 notes)
Answer (d): The root is $\frac{3-\sqrt5}{4}$, so the other is $\frac{3+\sqrt5}{4}$. Sum $=\frac32$, product $=\frac14$, giving $x^2-\frac32x+\frac14=0$, i.e. $4x^2-6x+1=0$.
Revise: Algebra (Class 11 notes)
Answer (a): $\frac{i-1}{i+1}=\frac{(i-1)(1-i)}{(1+i)(1-i)}=\frac{2i}{2}=i$. $i^1=i$ is not real but $i^2=-1$ is real, so $k=2$.
Revise: Algebra (Class 11 notes)
Answer (b): Taking tangent: $\frac{5x}{1-6x^2}=1$, so $6x^2+5x-1=0$, giving $x=\frac16$ or $x=-1$. Only $x=1/6$ truly satisfies it, but option b is the only one listing $1/6$ with the quadratic's other root.
Revise: Trigonometry (Class 11 notes)
Answer (a): $\sin^2x=\sin^2(\pi/4)$ has general solution $x=n\pi\pm\pi/4$.
Revise: Trigonometry (Class 11 notes)
Answer (d): For $(0,y)$: $\frac{|y-1|}{\sqrt2}=\sqrt2$, so $|y-1|=2$ and $y=3$ or $y=-1$.
Revise: Analytic geometry (Class 11 notes)
Answer (b): Using $abc+2fgh-af^2-bg^2-ch^2=0$ with $a=k,b=-1,c=0,h=\frac12,g=1,f=-\frac12$: $-\frac12-\frac k4+1=0$, so $k=2$.
Revise: Analytic geometry (Class 11 notes)
Answer (d): The question means direction ratios $2,3,-6$. Divide by $\sqrt{4+9+36}=7$ to get $\frac27,\frac37,-\frac67$.
Revise: Analytic geometry (Class 12 notes)
Answer (c): Vectors are linearly independent exactly when the only solution of the relation is the trivial one, x = y = z = 0.
Revise: Vectors (Class 11 notes)
Answer (b): Sum 2 has 1 way and sum 3 has 2 ways, so 3 favourable of 36 outcomes: 3/36 = 1/12.
Revise: Statistics and Probability (Class 11 notes)
Answer (a): $\lim\frac{\tan x+4x}{x}=\lim\frac{\tan x}{x}+4=1+4=5$.
Revise: Calculus (Class 11 notes)
Answer (d): $y=\sin(3x^2)$, so $\frac{dy}{dx}=\cos(3x^2)\cdot6x=6x\cos3x^2$.
Revise: Calculus (Class 11 notes)
Answer (c): $y''=12x^2-12=0$ gives $x=\pm1$, and $y''$ changes sign at both, so the inflection abscissas are $1,-1$.
Revise: Calculus (Class 11 notes)
Answer (a): Put $t=\sin x$: $\int_0^1e^t,dt=e-1$.
Revise: Calculus (Class 11 notes)
Answer (c): $f(1)=-2<0$ and $f(4)=16>0$, so a root lies in $(1,4)$; $f$ is increasing there, so exactly one root.
Revise: Computational methods (Class 11 notes)
Answer (c): Vertical component $=10\sin45^\circ=10\times\frac{1}{\sqrt2}=5\sqrt2,N$.
Revise: Mechanics (Class 11 notes)
Answer (d): Deceleration along the plane is $g\sin30^\circ=5,m/s^2$. Distance is $\frac{v^2}{2a}=\frac{400}{10}=40$ m.
Revise: Mechanics (Class 11 notes)
Answer (c): $J,s=(kg,m^2s^{-2}),s=kg,m^2s^{-1}$, the unit of angular momentum (and of Planck's constant).
Revise: Physical Quantities (Class 11 notes)
Answer (c): A cross product is perpendicular to both of the vectors that form it.
Revise: Magnetic Field (Class 12 notes)
Answer (a): If the first ball is at time $t$ and the second at $t-2$, equal heights give $40t-5t^2=40(t-2)-5(t-2)^2$, so $t=5$ s. Height $=200-125=75$ m.
Revise: Kinematics (Class 11 notes)
Answer (b): At the top only the horizontal velocity $u\cos45^\circ$ remains, so KE $=K\cos^2 45^\circ=K/2$.
Revise: Kinematics (Class 11 notes)
Answer (b): The largest static friction, just before motion begins, is called limiting friction.
Revise: Dynamics (Class 11 notes)
Answer (a): The Pragyan rover's LIBS instrument confirmed sulphur along with other elements such as aluminium, calcium, iron and oxygen.
Answer (c): The water she drinks adds its weight to the floating boat, which then displaces exactly that much extra water, so the lake level is unchanged.
Revise: Fluid Statics (Class 12 notes)
Answer (d): A bimetallic strip bends when heated because its two metals expand unequally, closing the alarm circuit.
Revise: Thermal Expansion (Class 11 notes)
Answer (a): High humidity slows evaporation of sweat, so cooling is poor and the body feels hottest at 99%.
Revise: Heat and Temperature (Class 11 notes)
Answer (b): Plate thickness $t=1+2=3$. Apparent shift of the mark is $t(1-\frac1\mu)=1$, so $1-\frac1\mu=\frac13$ and $\mu=1.5$.
Revise: Refraction at Plane Surface (Class 11 notes)
Answer (c): Reducing the aperture cuts the light collected, so the image becomes dimmer while its position and size stay the same.
Revise: Lenses (Class 11 notes)
Answer (c): Solids can support shear, so both longitudinal and transverse waves travel through rock.
Revise: Mechanical Waves (Class 12 notes)
Answer (c): Charge sits on the outer surface and capacitance $C=4\pi\varepsilon_0R$ depends only on the radius, so both hold equal charge.
Revise: Capacitor (Class 11 notes)
Answer (c): Maximum current needs external resistance matched to the internal resistance of the bank, which is generally achieved by a mixed grouping.
Revise: Electrical Circuit One (Class 12 notes)
Answer (d): Each wire sits in the magnetic field of the other, and same-direction currents give an attractive magnetic force.
Revise: Magnetic Field (Class 12 notes)
Answer (b): $L=\frac{\varepsilon}{|dI/dt|}=\frac{2}{1/10^{-3}}=2\times10^{-3},H=2,mH$.
Revise: Electromagnetic Induction (Class 12 notes)
Answer (c): $V=\sqrt{V_R^2+(V_L-V_C)^2}=\sqrt{40^2+30^2}=50,V$.
Revise: Alternating Currents (Class 12 notes)
Answer (a): The field is attributed to electric currents from the motion of molten conducting material in the outer core (dynamo effect). Of the options, the first is the closest.
Revise: Magnetic Properties of Materials (Class 12 notes)
Answer (d): Magnetic force is perpendicular to velocity, so it does no work: speed and energy stay fixed, only direction changes.
Revise: Magnetic Field (Class 12 notes)
Answer (c): Speed $\propto Z/n$. For $Li^{2+}$, $Z=3$ and first excited state $n=2$: $v'=v\cdot\frac32=1.5v$.
Revise: Quantization of Energy (Class 12 notes)
Answer (d): A nuclear holocaust means the widespread destruction and aftermath following nuclear explosions.
Revise: Nuclear Physics (Class 11 notes)
Answer (d): Oppenheimer led the Los Alamos laboratory that designed the atomic bomb in the Manhattan Project.
Answer (b): Net rates: $82-10=72$ and $19-10=9$. $72/9=8=2^3$, so 3 half-lives in $210,s$, giving $T_{1/2}=70,s$.
Revise: Radioactivity and Nuclear Reaction (Class 12 notes)
Answer (d): The output is 1 only when both inputs are 1, which is the AND operation.
Revise: Semiconductor Devices (Class 12 notes)
Answer (d): In an NPN transistor the majority carriers are electrons, which have higher mobility than holes, giving better response.
Revise: Semiconductor Devices (Class 12 notes)
Answer (a): Lavoisier showed that mass is neither created nor destroyed in a chemical reaction.
Revise: Stoichiometry (Class 11 notes)
Answer (b): A filled 3d subshell is extra stable, so one 4s electron moves to 3d: [Ar] 3d10 4s1.
Revise: Atomic Structure (Class 11 notes)
Answer (c): Fluorine has the highest electronegativity (4.0 on the Pauling scale).
Revise: Classification of Elements (Class 11 notes)
Answer (d): Nitrogen has three bond pairs and one lone pair (sp3), giving a pyramidal shape.
Revise: Chemical Bonding (Class 11 notes)
Answer (a): Blue vitriol is $\ce{CuSO4.5H2O}$.
Revise: Chemistry of Metals (Class 11 notes)
Answer (b): Brass is an alloy of copper and zinc.
Revise: Chemistry of Metals (Class 11 notes)
Answer (c): Nitrate is reduced to $NO$ by $FeSO_4$ and conc. $H_2SO_4$; $NO$ combines with $FeSO_4$ to give the brown ring of $\ce{FeSO4.NO}$.
Revise: Chemistry of Non-Metals (Class 11 notes)
Answer (d): Kipp's apparatus gives gas from a solid and a liquid without heating: H2S from FeS and acid, and also CO2 or H2.
Revise: Chemistry of Non-Metals (Class 11 notes)
Answer (a): The porphyrin ring of chlorophyll holds a central magnesium ion.
Revise: Bio-Inorganic Chemistry (Class 11 notes)
Answer (b): van't Hoff and Le Bel independently proposed the tetrahedral carbon atom in 1874.
Revise: Fundamental Principles (Class 11 notes)
Answer (c): $N_2+3H_2\rightleftharpoons2NH_3$ is the Haber process.
Revise: Modern Chemical Manufactures (Class 11 notes)
Answer (d): Michael Faraday isolated benzene in 1825 from compressed oil gas.
Revise: Aromatic Hydrocarbons (Class 11 notes)
Answer (a): Prussian blue is ferric ferrocyanide, Fe4[Fe(CN)6]3.
Revise: Study of Heavy Metals (Class 12 notes)
Answer (b): The uranium (U-238) series has mass numbers of the form 4n+2.
Revise: Nuclear Chemistry (Class 12 notes)
Answer (c): Bakelite forms from phenol and formaldehyde with loss of water; the others are addition polymers.
Revise: Chemistry in the Service to Mankind (Class 12 notes)
Answer (d): Partly filled d orbitals allow several oxidation states in transition metals.
Revise: Transition Metals (Class 12 notes)
Answer (a): Corrosive sublimate is mercuric chloride, $HgCl_2$. Calomel is $Hg_2Cl_2$.
Revise: Study of Heavy Metals (Class 12 notes)
Answer (b): Acidified dichromate oxidises a primary alcohol through acetaldehyde on to acetic acid.
Revise: Alcohols (Class 12 notes)
Answer (c): Formic acid HCOOH has one carbon, so it is methanoic acid.
Revise: Carboxylic Acids (Class 12 notes)
Answer (d): Ammoniacal silver nitrate is Tollens' reagent, used to detect aldehydes.
Revise: Aldehydes and Ketones (Class 12 notes)
Answer (a): With $Zn/NH_4Cl$ (neutral medium), nitrobenzene gives N-phenylhydroxylamine.
Revise: Nitro Compounds (Class 12 notes)
Answer (b): A Grignard reagent adds to a ketone C=O and hydrolysis gives a tertiary alcohol.
Revise: Organometallic Compounds (Class 12 notes)
Answer (c): KMnO4 is impure, decomposes and is not stable in solution, so it is a secondary standard.
Revise: Volumetric Analysis (Class 12 notes)
Answer (d): Rate depends on concentration, temperature and the nature of reactants; molecularity only describes the elementary step.
Revise: Chemical Kinetics (Class 12 notes)
Answer (a): Density is a ratio and does not depend on the amount of matter, so it is intensive. Mass, volume and enthalpy are extensive.
Revise: Chemical Thermodynamic (Class 12 notes)
Answer (d): A predicament is a difficult or confusing situation, which is a quandary.
Revise: Vocabulary and Word Formation (Class 11 notes)
Answer (c): Preferment means advancement to a higher position, i.e. promotion.
Revise: Vocabulary and Word Formation (Class 11 notes)
Answer (b): To gainsay is to deny or contradict.
Revise: Vocabulary and Word Formation (Class 11 notes)
Answer (a): Morbid means unhealthy or diseased, so the opposite is healthy.
Revise: Vocabulary and Word Formation (Class 11 notes)
Answer (b): Esteem means respect, and the opposite is disrespect or insult.
Revise: Vocabulary and Word Formation (Class 11 notes)
Answer (c): An agnostic holds that the existence of God cannot be known.
Revise: Vocabulary and Word Formation (Class 11 notes)
Answer (d): Sophism is clever but false argument meant to deceive.
Revise: Vocabulary and Word Formation (Class 11 notes)
Answer (a): Hold back means hesitate or restrain oneself, fitting the uncertainty.
Revise: Grammar and Usage (Class 11 notes)
Answer (b): 'Clear off' means go away, which fits telling children to take their football and leave.
Revise: Grammar and Usage (Class 11 notes)
Answer (b): We surrender to someone and wait for something.
Revise: Grammar and Usage (Class 11 notes)
Answer (c): The phrase is proceed from one site to another for quick supervision: from, for.
Revise: Grammar and Usage (Class 11 notes)
Answer (d): The idiom 'wink at' means to pretend not to see a fault, and one 'laughs at' others' errors, so the answer is at, at.
Revise: Grammar and Usage (Class 11 notes)
Answer (a): To carry the day means to win or be victorious.
Revise: Vocabulary and Word Formation (Class 11 notes)
Answer (a): Pro-se-CU-tion takes the primary stress on the third syllable.
Revise: Grammar and Usage (Class 11 notes)
Answer (b): Even if expresses concession: we will follow him even if he drives more slowly.
Revise: Grammar and Usage (Class 11 notes)
Answer (a): GPT stands for Generative Pre-trained Transformer.
Revise: Recent Trends in ICT (Class 12 notes)
Answer (a): MS-DOS accepts typed commands and has no graphical interface.
Revise: Computer Software and Operating System (Class 11 notes)
Answer (a): VGA is the Video Graphics Array display standard.
Revise: Computer System (Class 11 notes)
Answer (a): Python is the most widely used AI language thanks to libraries like TensorFlow and PyTorch.
Revise: Recent Trends in ICT (Class 12 notes)
Answer (b): Autonomous hazard detection and navigation helped the lander touch down safely.
Revise: Recent Trends in ICT (Class 12 notes)
Answer (c): A router forwards packets using IP addresses at the network layer.
Revise: Concept of Network and Data Communication (Class 12 notes)
Answer (c): $4\times1024=4096$ bytes.
Revise: Computer System (Class 11 notes)
Answer (c): $1011_2=8+2+1=11$ and $1111_2=8+4+2+1=15$.
Revise: Number System and Boolean Logic (Class 11 notes)
Answer (d): A .BAT file is a batch (script) file, which is not a system, backup or storage file, so none of the options applies.
Revise: Computer Software and Operating System (Class 11 notes)
Answer (b): Creeper (1971, written here as Cripper) is the earliest of these; Blaster, Sasser and Mydoom came decades later.
Revise: Information Security and Cyber Law (Class 11 notes)