Find the solution of y′′+4y′+4=0y'' + 4y' + 4 = 0y′′+4y′+4=0. | Mathematics I 2075

Mathematics I20755 marksNumerical: Second order ODESecond order linear differential equations

Find the solution of y′′+4y′+4=0y'' + 4y' + 4 = 0y′′+4y′+4=0. [5]

Differential equation: $y'' + 4y' + 4 = 0$ - Coefficients (interpreting as homogeneous constant-coefficient ODE): coefficient of $y''$ is $1$ , of $y'$ is $4$ , of $y$ is $4$ . Note on interpretation: As literally written, $y'' + 4y' + 4 = 0$ has a constant term $4$ rather than a $4y$ term, which ...

Differential equation: $y'' + 4y' + 4 = 0$ - Coefficients (interpreting as homogeneous constant-coefficient ODE): coefficient of $y''$ is $1$, of $y'$ is $4$, of $y$ is $4$. Note on interpretation: As literally written, $y'' + 4y' + 4 = 0$ has a constant term $4$ rather than a $4y$ term, which ...