Find the equation of the tangent at (1,3) to the curve y = x2 + 1. | Mathematics I 2079

Mathematics I20795 marksNumerical: tangent line equationTangents and velocity

Find the equation of the tangent at (1,3) to the curve $y = x^2 + 1$ . [5]

Find the equation of the tangent at (1,3) to the curve $y = x^2 + 1$. [5]

Curve: $y = x^2 + 1$ - Point of tangency: $(1, 3)$ Note on the point: Substituting $x = 1$ into the curve gives $y = 1^2 + 1 = 2$ , so the point $(1, 3)$ does not actually lie on the curve $y = x^2 + 1$ (the curve passes through $(1, 2)$ ). This appears to be a typo in the problem. I will solve u...

Curve: $y = x^2 + 1$ - Point of tangency: $(1, 3)$ Note on the point: Substituting $x = 1$ into the curve gives $y = 1^2 + 1 = 2$, so the point $(1, 3)$ does not actually lie on the curve $y = x^2 + 1$ (the curve passes through $(1, 2)$). This appears to be a typo in the problem. I will solve u...