If f(x,y) = 2x3 + x2y2 - y4, find fx(1,-2), fy(1,-1) and fyx(1,-1). | Mathematics I 2081

Mathematics I20815 marksNumerical: partial derivatives calculationPartial derivatives

If $f(x,y) = 2x^3 + x^2y^2 - y^4$ , find $f_x(1,-2)$ , $f_y(1,-1)$ and $f_{yx}(1,-1)$ . [5]

If $f(x,y) = 2x^3 + x^2y^2 - y^4$, find $f_x(1,-2)$, $f_y(1,-1)$ and $f_{yx}(1,-1)$. [5]

$f(x, y) = 2x^3 + x^2y^2 - y^4$ Required: - $fx(1, -2)$ - $fy(1, -1)$ - $f{yx}(1, -1)$ --- Differentiate with respect to $x$ (treat $y$ constant): $fx = 6x^2 + 2xy^2 - 0 = 6x^2 + 2xy^2$ Evaluate at $(1, -2)$ : $fx(1,-2) = 6(1)^2 + 2(1)(-2)^2 = 6 + 2(4) = 6 + 8 = 14$ --- Differentiate with re...

$$f(x, y) = 2x^3 + x^2y^2 - y^4$$ Required: - $fx(1, -2)$ - $fy(1, -1)$ - $f{yx}(1, -1)$ --- Differentiate with respect to $x$ (treat $y$ constant): $$fx = 6x^2 + 2xy^2 - 0 = 6x^2 + 2xy^2$$ Evaluate at $(1, -2)$: $$fx(1,-2) = 6(1)^2 + 2(1)(-2)^2 = 6 + 2(4) = 6 + 8 = 14$$ --- Differentiate with re...

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