Mathematics I20755 marksNumerical: continuity proofContinuity
Define continuity on an interval. Show that the function is continuous on the interval [-1,1]. f(x) = 1 - sqrt1 - x2
Define continuity on an interval. Show that the function is continuous on the interval $[-1,1]$. $f(x) = 1 - \sqrt{1 - x^2}$ [5]
- Function: $f(x) = 1 - \sqrt{1 - x^2}$ - Interval: $[-1, 1]$ (the problem writes $[1,-1]$, which is the closed interval between $-1$ and $1$) A function $f$ is continuous on a closed interval $[a, b]$ if: 1. $f$ is continuous at every interior point $c \in (a, b)$: $$\lim{x \to c} f(x) = f(c)$$ ...