Find the partial derivative of f(x, y) = x3 + 2x3y3 - 3y2 + x + y at ( | Mathematics I 2077

Mathematics I20775 marksNumerical: Partial derivatives at pointPartial derivatives

Find the partial derivative of $f(x, y) = x^3 + 2x^3y^3 - 3y^2 + x + y$ at (2,1). [5]

Function: $f(x, y) = x^3 + 2x^3y^3 - 3y^2 + x + y$ Point of evaluation: $(x, y) = (2, 1)$ Required: partial derivatives $\dfrac{\partial f}{\partial x}$ and $\dfrac{\partial f}{\partial y}$ evaluated at $(2,1)$ . --- $$\frac{\partial f}{\partial x} = \frac{\partial}{\partial x}\left(x^3 + 2x^3y^...

Function: $$f(x, y) = x^3 + 2x^3y^3 - 3y^2 + x + y$$ Point of evaluation: $(x, y) = (2, 1)$ Required: partial derivatives $\dfrac{\partial f}{\partial x}$ and $\dfrac{\partial f}{\partial y}$ evaluated at $(2,1)$. --- $$\frac{\partial f}{\partial x} = \frac{\partial}{\partial x}\left(x^3 + 2x^3y^...

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Find the partial derivative of f(x, y) = x3 + 2x3y3 - 3y2 + x + y at (2,1).