Physics20745 marksNumerical: Hall voltage calculationHall effect
A current of 50 A is established in a slab of copper 0.5 cm thick and 2 cm wide. The slab is placed in a magnetic field B of 1.5 T. The magnetic field is perpendicular to the plane of the slab and to the current. The free electron concentration in copper is 8.4 times 1028 electrons/m³. What will be
A current of 50 A is established in a slab of copper 0.5 cm thick and 2 cm wide. The slab is placed in a magnetic field B of 1.5 T. The magnetic field is perpendicular to the plane of the slab and to the current. The free electron concentration in copper is $8.4 \times 10^{28}$ electrons/m³. What will be the magnitude of the Hall voltage across the width of the slab? [5]
Quantity Value ------ Current, $I$ $50\ \text{A}$ Thickness, $t$ $0.5\ \text{cm} = 0.5\times10^{-2}\ \text{m}$ Width, $w$ $2\ \text{cm} = 2\times10^{-2}\ \text{m}$ Magnetic field, $B$ $1.5\ \text{T}$ Electron concentration, $n$ $8.4\times10^{28}\ \text{m}^{-3}$ Electron charge, $e$