A roulette wheel with moment of inertia I = 0.5 mathrmkgm2 rotating initially at 2 rev/sec coasts to a stop from the constant friction torque of bearing. If the torque is 0.4 Nm, how long does it take to stop?
A roulette wheel with moment of inertia $I = 0.5\ \mathrm{kgm^2}$ rotating initially at 2 rev/sec coasts to a stop from the constant friction torque of bearing. If the torque is 0.4 Nm, how long does it take to stop? [5]
Quantity Value ------ Moment of inertia, $I$ $0.5\ \text{kg m}^2$ Initial rotation rate, $n0$ $2\ \text{rev/s}$ Final rotation rate, $n$ $0\ \text{rev/s}$ Friction torque, $T$ $0.4\ \text{N m}$ Newton's second law for rotation: $T = I\alpha$, then rotational kinematics