Physics20815 marksNumerical: proton in magnetic fieldForce on a moving charge
A proton is accelerated through a potential difference of 200 V. It then enters a region where there is a magnetic field B = 0.5 T. The magnetic field is perpendicular to the direction of motion of the proton. Find the force experienced by the proton.
A proton is accelerated through a potential difference of 200 V. It then enters a region where there is a magnetic field B = 0.5 T. The magnetic field is perpendicular to the direction of motion of the proton. Find the force experienced by the proton. [5]
Quantity Value ------ Potential difference $V = 200$ V Magnetic field $B = 0.5$ T Angle between $\vec{v}$ and $\vec{B}$ $\theta = 90°$ Proton charge $q = e = 1.6 \times 10^{-19}$ C Proton mass $m = 1.67 \times 10^{-27}$ kg Energy conservation: $$qV = \frac{1}{2}mv^2 \implies v = \sqrt{\frac{2qV}{...